GMAT Practice Question: 2 x+y=12 |y| \leq 12 For how many ordered pairs (x, y)...
Question
2 x+y=12 |y| \leq 12 For how many ordered pairs (x, y) that are solutions of the system above are x and y both integers?
- 7
- 10
- 12
- 13
- 14
Topics: inequalities, simultaneous equations, number theory
Solution
Step 1
We first isolate y in the first equation, in order to use substitution into the absolute value inequality.
y = 12 - 2x
Step 2
We apply the constraint on y by substituting its expression into the absolute value inequality.
|12 - 2x| \le 12
Step 3
We convert the absolute value inequality into a compound inequality.
-12 \le 12 - 2x \le 12
Step 4
Statement: Solve the left part of the compound inequality for x by isolating x.
-12 \le 12 - 2x -24 \le -2x 12 \ge x
Step 5
Statement: Solve the right part of the compound inequality for x by isolating x.
12 - 2x \le 12 -2x \le 0 x \ge 0
Step 6
We combine the two results to find the range for x.
0 \le x \le 12
Step 7
We count the integer values from 0 to 12 inclusive to find the number of possible x values.
12 - 0 + 1 = 13
Answer
13
