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Alex has 4 \frac{1}{2} barrels of oil on hand and applies oil to three machines, using \frac{7}{8} barrel for each machine. Which of the following describes the amount of oil remaining after he applies the oil?

Explanation	Calculations	Help
$We use A to represent the initial amount of oil Alex has.$	$A = 4 \frac{1}{2} barrels$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We convert the mixed number into an improper fraction.$	$A = 4 \frac{1}{2} barrels A = \frac{4 \times 2 + 1}{2} barrels A = \frac{9}{2} barrels$
$We translate "using \frac{7}{8} barrel for each machine" into an equation for the oil used per machine.$	$m = \frac{7}{8} barrel$	Theory & Tactics Method Card TRANS2-B Click to view full details
$We calculate the total oil used for three machines by multiplying by three.$	$U = 3 \times \frac{7}{8} = \frac{21}{8} barrels$
$We subtract the oil used from the initial amount to find the remaining oil.$	$R = \frac{9}{2} - \frac{21}{8} R = \frac{36}{8} - \frac{21}{8} R = \frac{15}{8} barrels$	Theory & Tactics Method Card TRANS1-D Click to view full details
$We convert the improper fraction into a mixed number to interpret the remaining oil.$	$\frac{15}{8} = 1 \frac{7}{8} barrels$
$This shows the remaining oil is 1 \frac{7}{8} barrels, which corresponds to answer D.$	$Answer D$

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D

Alex has 4 \frac{1}{2} barrels of oil on hand and applies oil to three machines, using \frac{7}{8} barrel for each machine. Which of the following describes the amount of oil remaining after he applies the oil?

Explanation	Calculations	Help
$We use A to represent the initial amount of oil Alex has.$	$A = 4 \frac{1}{2} barrels$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We convert the mixed number into an improper fraction.$	$A = 4 \frac{1}{2} barrels A = \frac{4 \times 2 + 1}{2} barrels A = \frac{9}{2} barrels$
$We translate "using \frac{7}{8} barrel for each machine" into an equation for the oil used per machine.$	$m = \frac{7}{8} barrel$	Theory & Tactics Method Card TRANS2-B Click to view full details
$We calculate the total oil used for three machines by multiplying by three.$	$U = 3 \times \frac{7}{8} = \frac{21}{8} barrels$
$We subtract the oil used from the initial amount to find the remaining oil.$	$R = \frac{9}{2} - \frac{21}{8} R = \frac{36}{8} - \frac{21}{8} R = \frac{15}{8} barrels$	Theory & Tactics Method Card TRANS1-D Click to view full details
$We convert the improper fraction into a mixed number to interpret the remaining oil.$	$\frac{15}{8} = 1 \frac{7}{8} barrels$
$This shows the remaining oil is 1 \frac{7}{8} barrels, which corresponds to answer D.$	$Answer D$

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D