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At a literary festival, 12% of the attendees read both the featured novel and the accompanying magazine article. If 80% of those who read the featured novel did not read the magazine article, what percent of all attendees read the featured novel?

Explanation	Calculations	Help
$We first create an unknown for the percentage of attendees who read the featured novel.$	$N = percent of attendees who read the featured novel$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We translate "80 percent of those who read the featured novel did not read the magazine article" into a mathematical expression for the portion of novel readers who did read the article.$	$N - \frac{80}{100} N = \frac{20}{100} N$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We translate "12 percent of the attendees read both the featured novel and the accompanying magazine article" into a mathematical equation relating to our unknown.$	$\frac{20}{100} N = \frac{12}{100}$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We solve the equation for the unknown by isolating N .$	$N = \frac{\frac{12}{100}}{\frac{20}{100}} N = \frac{12}{20} N = \frac{3}{5} = 60%$

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C

At a literary festival, 12% of the attendees read both the featured novel and the accompanying magazine article. If 80% of those who read the featured novel did not read the magazine article, what percent of all attendees read the featured novel?

Explanation	Calculations	Help
$We first create an unknown for the percentage of attendees who read the featured novel.$	$N = percent of attendees who read the featured novel$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We translate "80 percent of those who read the featured novel did not read the magazine article" into a mathematical expression for the portion of novel readers who did read the article.$	$N - \frac{80}{100} N = \frac{20}{100} N$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We translate "12 percent of the attendees read both the featured novel and the accompanying magazine article" into a mathematical equation relating to our unknown.$	$\frac{20}{100} N = \frac{12}{100}$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We solve the equation for the unknown by isolating N .$	$N = \frac{\frac{12}{100}}{\frac{20}{100}} N = \frac{12}{20} N = \frac{3}{5} = 60%$

Scroll horizontally to view all columns

C