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If water is leaking from a certain tank at a constant rate of 1,200 milliliters per hour, how many seconds does it take for 1 milliliter of water to leak from the tank?

Explanation	Calculations	Help
$We first name the constant leakage rate r .$	$r = 1200 milliliters per hour$
$We then find the time in hours to leak one milliliter by dividing one milliliter by r .$	$t = \frac{1 milliliter}{r}$
$We then convert the time from hours to seconds by using that one hour equals 3600 seconds.$	$t = \frac{1}{1200} hours per milliliter t = \frac{1}{1200} \times 3600 seconds per milliliter t = 3 seconds per milliliter$	Theory & Tactics Method Card CALC4-A Click to view full details

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3 seconds

If water is leaking from a certain tank at a constant rate of 1,200 milliliters per hour, how many seconds does it take for 1 milliliter of water to leak from the tank?

Explanation	Calculations	Help
$We first name the constant leakage rate r .$	$r = 1200 milliliters per hour$
$We then find the time in hours to leak one milliliter by dividing one milliliter by r .$	$t = \frac{1 milliliter}{r}$
$We then convert the time from hours to seconds by using that one hour equals 3600 seconds.$	$t = \frac{1}{1200} hours per milliliter t = \frac{1}{1200} \times 3600 seconds per milliliter t = 3 seconds per milliliter$	Theory & Tactics Method Card CALC4-A Click to view full details

Scroll horizontally to view all columns

3 seconds