If x= \sqrt[5]{p^{15}} , y= \sqrt[5]{q^{15}} , q is not equal to 0, and p=3q, then \frac{x}{y}=

If x= \sqrt[5]{p^{15}} , y= \sqrt[5]{q^{15}} , q i... | Free GMAT Practice Question | GMAT Panda

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GMAT Quant — Algebra (Exponents)

If x = 5 p^{15}, y = 5 q^{15}, q is not equal to 0, and p = 3 q, then \frac{x}{y} =

Explanation	Calculations	Help
$We convert each fifth root to a fractional exponent and simplify$	$x = p^{15 \times \frac{1}{5}} = p^{3} y = q^{15 \times \frac{1}{5}} = q^{3}$	Theory & Tactics Method Card EXP0-B Click to view full details
$We form the ratio and rewrite it as a power of a fraction$	$\frac{x}{y} = \frac{p ^{3}}{q ^{3}} (\frac{p}{q})^{3}$	Theory & Tactics Method Card EXP0-B Click to view full details
$We substitute "p = 3q" into the expression and calculate the cube using Definition of an Exponent$	$(\frac{p}{q})^{3} = (\frac{3 q}{q})^{3} = 3^{3} 3^{3} = 27$	Theory & Tactics Method Card EXP0-A Click to view full details

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C

GMAT Quant — Algebra (Exponents)

If x = 5 p^{15}, y = 5 q^{15}, q is not equal to 0, and p = 3 q, then \frac{x}{y} =

Explanation	Calculations	Help
$We convert each fifth root to a fractional exponent and simplify$	$x = p^{15 \times \frac{1}{5}} = p^{3} y = q^{15 \times \frac{1}{5}} = q^{3}$	Theory & Tactics Method Card EXP0-B Click to view full details
$We form the ratio and rewrite it as a power of a fraction$	$\frac{x}{y} = \frac{p ^{3}}{q ^{3}} (\frac{p}{q})^{3}$	Theory & Tactics Method Card EXP0-B Click to view full details
$We substitute "p = 3q" into the expression and calculate the cube using Definition of an Exponent$	$(\frac{p}{q})^{3} = (\frac{3 q}{q})^{3} = 3^{3} 3^{3} = 27$	Theory & Tactics Method Card EXP0-A Click to view full details

Scroll horizontally to view all columns

C