In a field day at a school, each child who competed in n events and scored a total of p...

Question

In a field day at a school, each child who competed in n events and scored a total of p points was given an overall score of p/n+n. Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

GMAT Panda · Accepted Answer

The ratio is 10/9, which corresponds to option D. We first name the variables for Andrew's number of events and total points. n_A = 1 p_A = 9 We then calculate Andrew's overall score by applying the formula p/n+n. Andrew's score = p_A/n_A + n_A = 9/1 + 1 = 9 + 1 = 10 Next we name the variables for Jason's number of events and total points. n_J = 3 p_J = 5 + 6 + 7 = 18 We then calculate Jason's overall score using the same formula. Jason's score = p_J/n_J + n_J = 18/3 + 3 = 6 + 3 = 9 Finally, we form the ratio of Andrew's overall score to Jason's overall score. Andrew's scoreJason's score = 10/9

Explanation	Calculations	Help
$We first name the variables for Andrew's number of events and total points.$	$n_{A} = 1 p_{A} = 9$
$We then calculate Andrew's overall score by applying the formula \frac{p}{n} + n .$	$Andrew’s score = \frac{p _{A}}{n _{A}} + n_{A} = \frac{9}{1} + 1 = 9 + 1 = 10$
$Next we name the variables for Jason's number of events and total points.$	$n_{J} = 3 p_{J} = 5 + 6 + 7 = 18$
$We then calculate Jason's overall score using the same formula.$	$Jason’s score = \frac{p _{J}}{n _{J}} + n_{J} = \frac{18}{3} + 3 = 6 + 3 = 9$
$Finally, we form the ratio of Andrew's overall score to Jason's overall score.$	$\frac{Andrew’s score}{Jason’s score} = \frac{10}{9}$

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