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In a field day at a school, each child who competed in n events and scored a total of p points was given an overall score of \frac{p}{n} + n . Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

Explanation	Calculations	Help
$We first name the variables for Andrew's number of events and total points.$	$n_{A} = 1 p_{A} = 9$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We then calculate Andrew's overall score by applying the formula \frac{p}{n} + n .$	$Andrew’s score = \frac{p _{A}}{n _{A}} + n_{A} = \frac{9}{1} + 1 = 9 + 1 = 10$
$Next we name the variables for Jason's number of events and total points.$	$n_{J} = 3 p_{J} = 5 + 6 + 7 = 18$	Theory & Tactics Method Card TRANS1-A Click to view full details Theory & Tactics Method Card TRANS1-C Click to view full details
$We then calculate Jason's overall score using the same formula.$	$Jason’s score = \frac{p _{J}}{n _{J}} + n_{J} = \frac{18}{3} + 3 = 6 + 3 = 9$
$Finally, we form the ratio of Andrew's overall score to Jason's overall score.$	$\frac{Andrew’s score}{Jason’s score} = \frac{10}{9}$	Theory & Tactics Method Card TRANS2-E Click to view full details

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The ratio is \frac{10}{9}, which corresponds to option D.

In a field day at a school, each child who competed in n events and scored a total of p points was given an overall score of \frac{p}{n} + n . Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

Explanation	Calculations	Help
$We first name the variables for Andrew's number of events and total points.$	$n_{A} = 1 p_{A} = 9$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We then calculate Andrew's overall score by applying the formula \frac{p}{n} + n .$	$Andrew’s score = \frac{p _{A}}{n _{A}} + n_{A} = \frac{9}{1} + 1 = 9 + 1 = 10$
$Next we name the variables for Jason's number of events and total points.$	$n_{J} = 3 p_{J} = 5 + 6 + 7 = 18$	Theory & Tactics Method Card TRANS1-A Click to view full details Theory & Tactics Method Card TRANS1-C Click to view full details
$We then calculate Jason's overall score using the same formula.$	$Jason’s score = \frac{p _{J}}{n _{J}} + n_{J} = \frac{18}{3} + 3 = 6 + 3 = 9$
$Finally, we form the ratio of Andrew's overall score to Jason's overall score.$	$\frac{Andrew’s score}{Jason’s score} = \frac{10}{9}$	Theory & Tactics Method Card TRANS2-E Click to view full details

Scroll horizontally to view all columns

The ratio is \frac{10}{9}, which corresponds to option D.