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List T consists of the positive integers that are multiples of 8 and are less than 120 . What is the median of the integers in T ?

Explanation	Calculations	Help
$We note that the positive integers that are "multiples of 8 and are less than 120" form a list starting at 8 and ending at 112. We solve for the number of terms n .$	$8 + (n - 1) \times 8 = 112 (n - 1) \times 8 = 112 - 8 n - 1 = \frac{104}{8} n - 1 = 13 n = 14$	Theory & Tactics Method Card TRANS5-E Click to view full details
$We apply Average and Median Property of Evenly Spaced Sets to find that the median is the average of the first and last terms.$	$\frac{8 + 112}{2} = \frac{120}{2} = 60$	Theory & Tactics Method Card EVEN1-C Click to view full details

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C

List T consists of the positive integers that are multiples of 8 and are less than 120 . What is the median of the integers in T ?

Explanation	Calculations	Help
$We note that the positive integers that are "multiples of 8 and are less than 120" form a list starting at 8 and ending at 112. We solve for the number of terms n .$	$8 + (n - 1) \times 8 = 112 (n - 1) \times 8 = 112 - 8 n - 1 = \frac{104}{8} n - 1 = 13 n = 14$	Theory & Tactics Method Card TRANS5-E Click to view full details
$We apply Average and Median Property of Evenly Spaced Sets to find that the median is the average of the first and last terms.$	$\frac{8 + 112}{2} = \frac{120}{2} = 60$	Theory & Tactics Method Card EVEN1-C Click to view full details

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C