Max averaged $p q$ kilometers per hour on a trip that took him $r$ hours. Zoe completed the same trip in $\frac{2}{5}r$ hours. What was Zoe\u2019s average speed in kilometers per hour?

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Max averaged kilometers per hour on a trip that took him hours. Zoe completed the same trip in hours. What was Zoe\u2019s average speed in kilometers per hour?

Explanation	Calculations	Help
$We first use the distance formula to find the total distance of the trip in terms of the given variables.$	$D = (pq) \times r$	Theory & Tactics Method Card TRANS3-C Click to view full details
$We then express Zoe's average speed as the distance divided by her travel time.$	$v = \frac{D}{\frac{2}{5} r}$	Theory & Tactics Method Card TRANS3-C Click to view full details
$Substitute D = pq \times r into the expression for v and simplify to find the average speed.$	$v = \frac{5 D}{2 r} = \frac{5 ( pq \times r )}{2 r} = \frac{5 pq r}{2 r} = \frac{5}{2} pq$

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B

Max averaged kilometers per hour on a trip that took him hours. Zoe completed the same trip in hours. What was Zoe\u2019s average speed in kilometers per hour?

Explanation	Calculations	Help
$We first use the distance formula to find the total distance of the trip in terms of the given variables.$	$D = (pq) \times r$	Theory & Tactics Method Card TRANS3-C Click to view full details
$We then express Zoe's average speed as the distance divided by her travel time.$	$v = \frac{D}{\frac{2}{5} r}$	Theory & Tactics Method Card TRANS3-C Click to view full details
$Substitute D = pq \times r into the expression for v and simplify to find the average speed.$	$v = \frac{5 D}{2 r} = \frac{5 ( pq \times r )}{2 r} = \frac{5 pq r}{2 r} = \frac{5}{2} pq$

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B