Morgan has a collection of 10 gift baskets, and th... | Free GMAT Practice Question | GMAT Panda

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Morgan has a collection of 10 gift baskets, and the average number of chocolates per basket is m . If she replaces a basket that contains 14 chocolates with a basket that contains 20 chocolates, what is the average number of chocolates per basket for the new collection, in terms of m ?

Explanation	Calculations	Help
$We start by defining the total number of chocolates across all 10 baskets and expressing it in terms of the given average.$	$T = 10 m$	Theory & Tactics Method Card TRANS1-A Click to view full details Theory & Tactics Method Card TRANS3-F Click to view full details
$We calculate the updated total after removing the basket with 14 chocolates and adding the basket with 20 chocolates.$	$T_{new} = T - 14 + 20$	Theory & Tactics Method Card TRANS1-D Click to view full details Theory & Tactics Method Card TRANS1-C Click to view full details
$We find the new average by dividing the updated total by 10 and simplifying the resulting expression.$	$\frac{T _{new}}{10} = \frac{10 m + 6}{10} = m + \frac{6}{10} = m + \frac{2 \times 3}{2 \times 5} = m + \frac{3}{5}$	Theory & Tactics Method Card FDPR2-A Click to view full details

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A

Morgan has a collection of 10 gift baskets, and the average number of chocolates per basket is m . If she replaces a basket that contains 14 chocolates with a basket that contains 20 chocolates, what is the average number of chocolates per basket for the new collection, in terms of m ?

Explanation	Calculations	Help
$We start by defining the total number of chocolates across all 10 baskets and expressing it in terms of the given average.$	$T = 10 m$	Theory & Tactics Method Card TRANS1-A Click to view full details Theory & Tactics Method Card TRANS3-F Click to view full details
$We calculate the updated total after removing the basket with 14 chocolates and adding the basket with 20 chocolates.$	$T_{new} = T - 14 + 20$	Theory & Tactics Method Card TRANS1-D Click to view full details Theory & Tactics Method Card TRANS1-C Click to view full details
$We find the new average by dividing the updated total by 10 and simplifying the resulting expression.$	$\frac{T _{new}}{10} = \frac{10 m + 6}{10} = m + \frac{6}{10} = m + \frac{2 \times 3}{2 \times 5} = m + \frac{3}{5}$	Theory & Tactics Method Card FDPR2-A Click to view full details

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A