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On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

Explanation	Calculations	Help
$We first create an unknown for the percentage of passengers who held round-trip tickets.$	$R = percent of passengers with round-trip tickets$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We translate "60 percent of the passengers with round-trip tickets did not take their cars aboard the ship", which means that the remaining percent of those passengers did take their cars.$	$R - \frac{60}{100} R = \frac{40}{100} R$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We translate "20 percent of the ship's passengers held round-trip tickets and also took their cars aboard the ship" as the fraction of all passengers who both held round-trip tickets and took their cars.$	$\frac{40}{100} R = \frac{20}{100}$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We solve the linear equation for the unknown by isolating it.$	$\frac{40}{100} R = \frac{20}{100} R = \frac{\frac{20}{100}}{\frac{40}{100}} = \frac{20}{40} = \frac{1}{2} = 50%$	Theory & Tactics Method Card EQUA1-A Click to view full details

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On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

Explanation	Calculations	Help
$We first create an unknown for the percentage of passengers who held round-trip tickets.$	$R = percent of passengers with round-trip tickets$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We translate "60 percent of the passengers with round-trip tickets did not take their cars aboard the ship", which means that the remaining percent of those passengers did take their cars.$	$R - \frac{60}{100} R = \frac{40}{100} R$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We translate "20 percent of the ship's passengers held round-trip tickets and also took their cars aboard the ship" as the fraction of all passengers who both held round-trip tickets and took their cars.$	$\frac{40}{100} R = \frac{20}{100}$	Theory & Tactics Method Card TRANS2-A Click to view full details
$We solve the linear equation for the unknown by isolating it.$	$\frac{40}{100} R = \frac{20}{100} R = \frac{\frac{20}{100}}{\frac{40}{100}} = \frac{20}{40} = \frac{1}{2} = 50%$	Theory & Tactics Method Card EQUA1-A Click to view full details

Scroll horizontally to view all columns

50%