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The average (arithmetic mean) of the positive integers p, q, and r is 7 . If p < q < r, what is the greatest possible value of r ?

Explanation	Calculations	Help
$We translate the statement pq\text{ and }, $\textbf{" is 7"}}$ into an equation.$	$\frac{p + q + r}{3} = 7$	Theory & Tactics Method Card FDPR0-A Click to view full details
$We multiply both sides of the equation by 3 to find the sum of the three integers.$	$p + q + r = 21$
$To maximize r under the conditions "positive integers" and p < q < r, we choose the smallest values for p and q .$	$p = 1 q = 2$
$We substitute p and q into the sum to solve for r .$	$r = 21 - 1 - 2 = 18$

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C

The average (arithmetic mean) of the positive integers p, q, and r is 7 . If p < q < r, what is the greatest possible value of r ?

Explanation	Calculations	Help
$We translate the statement pq\text{ and }, $\textbf{" is 7"}}$ into an equation.$	$\frac{p + q + r}{3} = 7$	Theory & Tactics Method Card FDPR0-A Click to view full details
$We multiply both sides of the equation by 3 to find the sum of the three integers.$	$p + q + r = 21$
$To maximize r under the conditions "positive integers" and p < q < r, we choose the smallest values for p and q .$	$p = 1 q = 2$
$We substitute p and q into the sum to solve for r .$	$r = 21 - 1 - 2 = 18$

Scroll horizontally to view all columns

C