The population of a town increased by $0.6\%$ over one year. By what fraction did the population increase during that period?

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The population of a town increased by over one year. By what fraction did the population increase during that period?

Explanation	Calculations	Help
$We express the as a fraction of the original population by dividing by 100.$	$0.6% = \frac{0.6}{100}$	Theory & Tactics Method Card FDPR4-A Click to view full details
$We write as the fraction and combine it with the division by 100.$	$0.6 = \frac{6}{10} \frac{0.6}{100} = \frac{\frac{6}{10}}{100} = \frac{6}{10} \times \frac{1}{100}$	Theory & Tactics Method Card FDPR1-A Click to view full details
$We simplify the resulting fraction by canceling the common factor of 2.$	$= \frac{6}{10} \times \frac{1}{100} = \frac{6}{1000} = \frac{2 \times 3}{2 \times 500} = \frac{3}{500}$	Theory & Tactics Method Card FDPR2-A Click to view full details

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A

The population of a town increased by over one year. By what fraction did the population increase during that period?

Explanation	Calculations	Help
$We express the as a fraction of the original population by dividing by 100.$	$0.6% = \frac{0.6}{100}$	Theory & Tactics Method Card FDPR4-A Click to view full details
$We write as the fraction and combine it with the division by 100.$	$0.6 = \frac{6}{10} \frac{0.6}{100} = \frac{\frac{6}{10}}{100} = \frac{6}{10} \times \frac{1}{100}$	Theory & Tactics Method Card FDPR1-A Click to view full details
$We simplify the resulting fraction by canceling the common factor of 2.$	$= \frac{6}{10} \times \frac{1}{100} = \frac{6}{1000} = \frac{2 \times 3}{2 \times 500} = \frac{3}{500}$	Theory & Tactics Method Card FDPR2-A Click to view full details

Scroll horizontally to view all columns

A