GMAT Practice Question: The sum S of the first n consecutive positive even integers is given by S=n(n+1)...
Question
The sum S of the first n consecutive positive even integers is given by S=n(n+1). For what value of n is this sum equal to 110 ?
- 10
- 11
- 12
- 13
- 14
Topics: consecutive integers, sums of integers, odds/evens
Solution
Step 1
We translate the question’s phrase
n(n+1) = 110
Step 2
We rewrite the expression in standard quadratic form by expanding and moving all terms to one side
n^2 + n - 110 = 0
Step 3
We factor the quadratic expression to find its roots
(n + 11)(n - 10) = 0
Step 4
Since n represents a count of terms (and must be a positive integer), we discard the negative solution and take the positive one
n = 10
Answer
10
