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If a, b, c, and d are consecutive even integers and a < b < c < d, then a + b is how much less than c + d ?

Explanation	Calculations	Help
$Express b as the next even integer after a .$	$b = a + 2$
$Express c as the next even integer after b .$	$c = a + 4$
$Express d as the next even integer after c .$	$d = a + 6$
$Write the expression for the sum of a and b .$	$a + b = a + (a + 2)$
$Simplify the expression for a + b .$	$a + (a + 2) = 2 a + 2$
$Write the expression for the sum of c and d .$	$c + d = (a + 4) + (a + 6)$
$Simplify the expression for c + d .$	$(a + 4) + (a + 6) = 2 a + 10$
$Compute the difference between the sums to find how much less a + b is than c + d .$	$(2 a + 10) - (2 a + 2) = 8$

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If a, b, c, and d are consecutive even integers and a < b < c < d, then a + b is how much less than c + d ?

Explanation	Calculations	Help
$Express b as the next even integer after a .$	$b = a + 2$
$Express c as the next even integer after b .$	$c = a + 4$
$Express d as the next even integer after c .$	$d = a + 6$
$Write the expression for the sum of a and b .$	$a + b = a + (a + 2)$
$Simplify the expression for a + b .$	$a + (a + 2) = 2 a + 2$
$Write the expression for the sum of c and d .$	$c + d = (a + 4) + (a + 6)$
$Simplify the expression for c + d .$	$(a + 4) + (a + 6) = 2 a + 10$
$Compute the difference between the sums to find how much less a + b is than c + d .$	$(2 a + 10) - (2 a + 2) = 8$

Scroll horizontally to view all columns

8