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For each trip, a taxicab company charges 4.25 dollars for the first mile and 2.65 dollars for each additional mile or fraction thereof. If the total charge for a certain trip was 62.55 dollars, how many miles at most was the trip?

Explanation	Calculations	Help
$We first define a variable for the number of additional miles charged.$	$k = number of additional miles charged$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We translate ("the total charge for a certain trip was 62.55 dollars") and we note that ("sum of") the first-mile charge and the additional-mile charges equals 62.55.$	$4.25 + 2.65 \times k = 62.55$	Theory & Tactics Method Card TRANS1-B Click to view full details Theory & Tactics Method Card TRANS1-C Click to view full details
$We isolate the number of additional miles by subtracting the first-mile charge from the total and dividing by the rate per additional mile.$	$4.25 + 2.65 \times k = 62.55 2.65 \times k = 62.55 - 4.25 = 58.30 k = \frac{58.30}{2.65} = 22$	Theory & Tactics Method Card EQUA1-A Click to view full details
$We add the initial mile back to find the maximum total miles for the trip.$	$m = 1 + k = 1 + 22 = 23$

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The trip was at most 23 miles, so the answer is Answer C .

For each trip, a taxicab company charges 4.25 dollars for the first mile and 2.65 dollars for each additional mile or fraction thereof. If the total charge for a certain trip was 62.55 dollars, how many miles at most was the trip?

Explanation	Calculations	Help
$We first define a variable for the number of additional miles charged.$	$k = number of additional miles charged$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We translate ("the total charge for a certain trip was 62.55 dollars") and we note that ("sum of") the first-mile charge and the additional-mile charges equals 62.55.$	$4.25 + 2.65 \times k = 62.55$	Theory & Tactics Method Card TRANS1-B Click to view full details Theory & Tactics Method Card TRANS1-C Click to view full details
$We isolate the number of additional miles by subtracting the first-mile charge from the total and dividing by the rate per additional mile.$	$4.25 + 2.65 \times k = 62.55 2.65 \times k = 62.55 - 4.25 = 58.30 k = \frac{58.30}{2.65} = 22$	Theory & Tactics Method Card EQUA1-A Click to view full details
$We add the initial mile back to find the maximum total miles for the trip.$	$m = 1 + k = 1 + 22 = 23$

Scroll horizontally to view all columns

The trip was at most 23 miles, so the answer is Answer C .