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Of the 20 members of a kitchen crew, 17 can use the meat-cutting machine, 18 can use the bread-slicing machine, and 15 can use both machines. If one member of the crew is to be chosen at random, what is the probability that the member chosen will be someone who cannot use either machine?

Explanation	Calculations	Help
$We name variables for each group and the total crew.$	$M = 17 B = 18 I = 15 T = 20$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We use the inclusion-exclusion principle to find how many can use at least one machine.$	$M + B - I = 17 + 18 - 15 = 20$	Theory & Tactics Method Card SET1 Click to view full details
$We subtract those who can use at least one machine from the total to find those who cannot use either.$	$T - 20 = 0$
$We calculate the probability by dividing the number who cannot use either machine by the total crew.$	$\frac{0}{T} = 0$	Theory & Tactics Method Card PC1-B Click to view full details

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Of the 20 members of a kitchen crew, 17 can use the meat-cutting machine, 18 can use the bread-slicing machine, and 15 can use both machines. If one member of the crew is to be chosen at random, what is the probability that the member chosen will be someone who cannot use either machine?

Explanation	Calculations	Help
$We name variables for each group and the total crew.$	$M = 17 B = 18 I = 15 T = 20$	Theory & Tactics Method Card TRANS1-A Click to view full details
$We use the inclusion-exclusion principle to find how many can use at least one machine.$	$M + B - I = 17 + 18 - 15 = 20$	Theory & Tactics Method Card SET1 Click to view full details
$We subtract those who can use at least one machine from the total to find those who cannot use either.$	$T - 20 = 0$
$We calculate the probability by dividing the number who cannot use either machine by the total crew.$	$\frac{0}{T} = 0$	Theory & Tactics Method Card PC1-B Click to view full details

Scroll horizontally to view all columns

0