GMAT Linear Equations Explained — X = \frac{1}{6} gt^2 In the formula shown, if g is a

x = \frac{1}{6} g t^{2} In the formula shown, if g is a constant and x = - 6 when t = 2, what is the value of x when t = 4?

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$We let x be the displacement, t be the time, and g be the constant of proportionality in the given formula.$	$x = \frac{1}{6} g t^{2}$
$We substitute x = -6 and t = 2 into the formula and solve for g.$	$- 6 = \frac{1}{6} g \times 2^{2} = \frac{1}{6} g \times 4 = \frac{4}{6} g g = - 6 \times \frac{6}{4} = - 9$	Theory & Tactics Method Card EQUA1-A Click to view full details
$We substitute g = -9 and t = 4 into the formula to calculate x.$	$x = \frac{1}{6} \times (- 9) \times 4^{2} = \frac{1}{6} \times (- 9) \times 16 = \frac{- 144}{6} = - 24$	Theory & Tactics Method Card EQUA1-A Click to view full details

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The value of x is -24.